Section01_定义

基本概念

  1. 矩阵 A=(a11a12⋯a1na21a22⋯a2n⋮⋮⋱⋮am1am2⋯amn)≜(aij)m×n\boldsymbol{A} = \left( \begin{matrix} a_{11} & a_{12} &\cdots & a_{1n} \\ a_{21} & a_{22} &\cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m1} & a_{m2} &\cdots & a_{mn} \\ \end{matrix} \right)\triangleq (a_{ij})_{m\times n}
    1. 若 ∀ aij=0,A=0\forall\ a_{ij} = 0, \boldsymbol{A} = \boldsymbol{0}
    2. 若 m=nm=n,A\boldsymbol{A} 为方阵
  2. 同型矩阵与矩阵相等 Am×n,Bm×n\boldsymbol{A}_{m\times n},\boldsymbol{B}_{m\times n} 称谓同型矩阵,设 A=(aij)m×n,B=(bij)m×n\boldsymbol{A} = (a_{ij})_{m\times n}, \boldsymbol{B} = (b_{ij})_{m\times n},若 ∀ aij=bij\forall\ a_{ij}= b_{ij},则 A=B\boldsymbol{A} = \boldsymbol{B}
  3. 三则运算
    1. Am×n=(a11a12⋯a1na21a22⋯a2n⋮⋮⋱⋮am1am2⋯amn),Bm×n=(b11b12⋯b1nb21b22⋯b2n⋮⋮⋱⋮bm1bm2⋯bmn)\boldsymbol{A}_{m\times n} = \left( \begin{matrix} a_{11} & a_{12} &\cdots & a_{1n} \\ a_{21} & a_{22} &\cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m1} & a_{m2} &\cdots & a_{mn} \\ \end{matrix} \right), \boldsymbol{B}_{m\times n} = \left( \begin{matrix} b_{11} & b_{12} &\cdots & b_{1n} \\ b_{21} & b_{22} &\cdots & b_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ b_{m1} & b_{m2} &\cdots & b_{mn} \\ \end{matrix} \right) A±B=(a11±b11a12±b12⋯a1n±b1na21±b21a22±b22⋯a2n±b2n⋮⋮⋱⋮am1±bm1am2±bm2⋯amn±bmn)=(aij±bij)m×n \boldsymbol{A}\pm \boldsymbol{B} = \left( \begin{matrix} a_{11}\pm b_{11} & a_{12}\pm b_{12} & \cdots & a_{1n}\pm b_{1n} \\ a_{21}\pm b_{21} & a_{22}\pm b_{22} & \cdots & a_{2n}\pm b_{2n} \\ \vdots &\vdots &\ddots & \vdots \\ a_{m1}\pm b_{m1} & a_{m2}\pm b_{m2} & \cdots & a_{mn}\pm b_{mn} \\ \end{matrix} \right) = (a_{ij}\pm b_{ij})_{m\times n}
    2. k⋅A=(ka11ka12⋯ka1nka21ka22⋯ka2n⋮⋮⋱⋮kam1kam2⋯kamn)=(kaij)m×nk\cdot \boldsymbol{A} = \left( \begin{matrix} ka_{11} & ka_{12} & \cdots & ka_{1n} \\ ka_{21} & ka_{22} & \cdots & ka_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ ka_{m1} & ka_{m2} & \cdots & ka_{mn} \end{matrix} \right) = (ka_{ij})_{m\times n}
    3. Am×n=(a11a12⋯a1na21a22⋯a2n⋮⋮⋱⋮am1am2⋯amn),Bn×s=(b11b12⋯b1sb21b22⋯b2s⋮⋮⋱⋮bn1bn2⋯bns)\boldsymbol{A}_{m\times n} = \left( \begin{matrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m1} & a_{m2} & \cdots & a_{mn} \end{matrix} \right), \boldsymbol{B}_{n\times s} = \left( \begin{matrix} b_{11} & b_{12} & \cdots & b_{1s} \\ b_{21} & b_{22} & \cdots & b_{2s} \\ \vdots & \vdots & \ddots & \vdots \\ b_{n1} & b_{n2} & \cdots & b_{ns} \end{matrix} \right) AB=Cm×s=(cij)m×scij=ai1b1j+ai2b2j+⋯+ainbnj \begin{split} &\boldsymbol{AB} = \boldsymbol{C}_{m\times s} = (c_{ij})_{m\times s} \\ &c_{ij} = a_{i 1}b_{1j} + a_{i2}b_{2j} +\cdots + a_{in}b_{nj} \end{split}

      Notes

      1. A≠0,B≠0⇏AB≠0\boldsymbol{A} \ne \boldsymbol{0}, \boldsymbol{B}\ne \boldsymbol{0} \nRightarrow \boldsymbol{AB}\ne \boldsymbol{0}

        如 A=(1111)≠0,B=(1−1−11)≠0\boldsymbol{A} = \left( \begin{matrix} 1 & 1 \\ 1 & 1 \end{matrix} \right) \ne \boldsymbol{0}, \boldsymbol{B} = \left( \begin{matrix} 1 & -1 \\ -1 & 1 \\ \end{matrix} \right)\ne \boldsymbol{0} 但 AB=0\boldsymbol{AB} = \boldsymbol{0}

      2. A≠0⇏Ak≠0\boldsymbol{A} \ne \boldsymbol{0} \nRightarrow \boldsymbol{A}^{k} \ne \boldsymbol{0}

        如 A=(0100)≠0\boldsymbol{A} = \left( \begin{matrix} 0 & 1 \\ 0 & 0 \end{matrix} \right)\ne \boldsymbol{0} 但 A2=0\boldsymbol{A}^{2} = \boldsymbol{0}

      3. AB\boldsymbol{AB} 与 BA\boldsymbol{BA} 不一定相等
      4. 对于 f(x)=anxn+⋯+a1x+a0f(x) = a_{n}x^{n}+\cdots + a_{1}x + a_{0},将 An×n\boldsymbol{A}_{n\times n} 代入,则 f(A)=anAn+⋯+a1A+a0Ef(\boldsymbol{A}) = a_{n}\boldsymbol{A}^{n} + \cdots + a_{1}\boldsymbol{A}+a_{0}\boldsymbol{E},f(A)f(\boldsymbol{A}) 称为 A\boldsymbol{A} 的矩阵多项式,==f(A)f(\boldsymbol{A}) 可像多项式一样处理==

        如 x2−x−2⇒(x+1)(x−2)A2−A−2E⇒(A+1)(A−2) \begin{split} x^{2} - x - 2 & \Rightarrow (x+1)(x-2) \\ \boldsymbol{A}^{2} - \boldsymbol{A} - 2 \boldsymbol{E} & \Rightarrow (\boldsymbol{A}+1)(\boldsymbol{A}-2) \end{split}

      5. 线性方程组的矩阵形式 A=(a11a12⋯a1na21a22⋯a2n⋮⋮⋱⋮am1am2⋯amn)x=(x1x2⋮xn)β=(b1b2⋮bm)AX=0⇔{a11x1+a12x2+⋯+a1nxn=0⋯am1x1+am2x2+⋯+amnxn=0AX=β⇔{a11x1+a12x2+⋯+a1nxn=b1⋯am1x1+am2x2+⋯+amnxn=bm \begin{split} & \boldsymbol{A} = \left( \begin{matrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m1} & a_{m2} & \cdots & a_{mn} \end{matrix} \right) \\ & \boldsymbol{x} = \left( \begin{matrix} x_{1}\\ x_{2}\\ \vdots\\x_{n} \end{matrix} \right)\quad \boldsymbol{\beta} = \left( \begin{matrix} b_{1} \\ b_{2} \\\vdots \\b_{m} \end{matrix} \right) \\\\ & \boldsymbol{AX} = \boldsymbol{0} \Leftrightarrow \begin{cases} a_{11}x_{1} + a_{12}x_{2} + \cdots + a_{1n}x_{n} = 0 \\ \cdots \\ a_{m1}x_{1} + a_{m2}x_{2} + \cdots + a_{mn}x_{n} = 0 \\ \end{cases} \\ & \boldsymbol{AX} = \boldsymbol{\beta} \Leftrightarrow \begin{cases} a_{11}x_{1} + a_{12}x_{2} + \cdots + a_{1n}x_{n} = b_{1} \\ \cdots \\ a_{m1}x_{1} + a_{m2}x_{2} + \cdots + a_{mn}x_{n} = b_{m} \\ \end{cases} \end{split}
  4. 伴随矩阵 对于 A\boldsymbol{A} 为 n×nn\times n 的方阵,则称 A∗=(A11A21⋯An1A12A22⋯An2⋮⋮⋱⋮A1nA2n⋯Ann)\boldsymbol{A}^{*} = \left( \begin{matrix} A_{11} & A_{21} & \cdots & A_{n1} \\ A_{12} & A_{22} & \cdots & A_{n2} \\ \vdots & \vdots & \ddots & \vdots \\ A_{1n} & A_{2n} & \cdots & A_{nn} \\ \end{matrix} \right) 为 A\boldsymbol{A} 的伴随矩阵 (注意此处为各元素对应的代数余子式组成矩阵的转置)
    • 注 AA∗=∣A∣E\boldsymbol{AA}^{*} = \vert \boldsymbol{A} \vert \boldsymbol{E}

Q1 矩阵研究什么

背景 对于方程 ax=bax=b

  1. a≠0a\ne0 时,1a⋅a=1\frac{1}{a}\cdot a = 1,则 1a⋅ax=1ab⇒x=1ab\frac{1}{a}\cdot ax = \frac{1}{a}b\Rightarrow x = \frac{1}{a}b
  2. a=0a = 0 {b=0,无数解b≠0,无解\begin{cases} b = 0, & \text{无数解} \\ b \ne 0, & \text{无解} \end{cases}

相似问题 对于方程组 AX=β\boldsymbol{AX} = \boldsymbol{\beta}

  1. 对于 An×n\boldsymbol{A}_{n\times n} 若 ∃ Bn×n\exists\ \boldsymbol{B}_{n\times n},使得 BA=E\boldsymbol{BA} = \boldsymbol{E} (==逆矩阵==),则 AX=β⇒BAX=Bβ⇒X=Bβ\boldsymbol{AX}=\boldsymbol{\beta}\Rightarrow \boldsymbol{BAX} = \boldsymbol{B\beta}\Rightarrow \boldsymbol{X} = \boldsymbol{B\beta}
  2. {An×n,但不满秩Am×n,且m≠n\begin{cases} \boldsymbol{A}_{n\times n}, \text{但不满秩} \\ \boldsymbol{A}_{m\times n}, \text{且} m \ne n \end{cases} (==矩阵的秩==)

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